View Single Post
  #10 (permalink)  
Old 09-24-2008, 01:51 AM
steveX's Avatar
steveX
 
Location: United Arab Emirates
Posts: n/a
Default

I will like to make a fair comparison.

the 95 rx-7 mpg is 15city and 22hi-way non turbo.

the 95 buick 3800 (3.8) mpg is 17city and 25 hi-way non s/c.

the 95 toyota corolla 1.8 mpg is 26city and 35 hi-way 132hp.

If a rx7 truly pose a 1.3 liter, why does it burn almost the same amount of air/fuel has the 3.8?. and no way close to the Toyota 1.8 liter.

here is my reason. The 13b 1.3 so-call liter has two rotor. each rotor has three sides. the two rotor, rotate around in its bore and rotate the crankshaft/intermittent shaft. In order for the rotor to rotate the crankshaft once. All three sides of the the rotor must be consume with air and fuel. this air and fuel must burn three time in order to rotate the crankshaft ONCE.

so in order to rotate the crankshaft once. The 1.3 liter rotatory engine will require three times the two rotors cubic inch air/fuel volume . Which leave us with the formula 1.3 (two rotor chamber cubic inch) x 3 (rotor sides) = 3.9 liter
Mazda feel 1.3 liter will sell the car to the CHEAP AMERICAN`T, but the never question of fuel consumption for such a small engine never hit the buyer...HYPE sells.

The 3.8 and other engine perform 4 stroke (except 2 stroke) to rotate the crankshaft once. Only at one point in this four stroke, power is created.


An engine is a air pump. the amount of air and fuel you put in it will equate to the amount of power .

Last edited by steveX : 09-24-2008 at 01:58 AM.
Reply With Quote